mysqli::real_connect
You can avoid all character escaping issues (on the PHP side) if you use prepare() and bind_param(), as an alternative to placing arbitrary string values in SQL statements. This works because bound parameter values are NOT passed via the SQL statement syntax.
mysqli::real_escape_string
mysqli_real_escape_string
(PHP 5)
mysqli::real_escape_string -- mysqli_real_escape_string — Escapes special characters in a string for use in an SQL statement, taking into account the current charset of the connection
Beschreibung
Objektorientierter Stil
string mysqli::real_escape_string
( string $escapestr
)
Prozeduraler Stil
This function is used to create a legal SQL string that you can use in an SQL statement. The given string is encoded to an escaped SQL string, taking into account the current character set of the connection.
Parameter-Liste
- link
-
Nur bei prozeduralem Aufruf: Ein von mysqli_connect() oder mysqli_init() zurückgegebenes Verbindungsobjekt.
- escapestr
-
The string to be escaped.
Characters encoded are NUL (ASCII 0), \n, \r, \, ', ", and Control-Z.
Rückgabewerte
Returns an escaped string.
Beispiele
Beispiel #1 mysqli::real_escape_string() example
Objektorientierter Stil
<?php
$mysqli = new mysqli("localhost", "my_user", "my_password", "world");
/* check connection */
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
$mysqli->query("CREATE TEMPORARY TABLE myCity LIKE City");
$city = "'s Hertogenbosch";
/* this query will fail, cause we didn't escape $city */
if (!$mysqli->query("INSERT into myCity (Name) VALUES ('$city')")) {
printf("Error: %s\n", $mysqli->sqlstate);
}
$city = $mysqli->real_escape_string($city);
/* this query with escaped $city will work */
if ($mysqli->query("INSERT into myCity (Name) VALUES ('$city')")) {
printf("%d Row inserted.\n", $mysqli->affected_rows);
}
$mysqli->close();
?>
Prozeduraler Stil
<?php
$link = mysqli_connect("localhost", "my_user", "my_password", "world");
/* check connection */
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
mysqli_query($link, "CREATE TEMPORARY TABLE myCity LIKE City");
$city = "'s Hertogenbosch";
/* this query will fail, cause we didn't escape $city */
if (!mysqli_query($link, "INSERT into myCity (Name) VALUES ('$city')")) {
printf("Error: %s\n", mysqli_sqlstate($link));
}
$city = mysqli_real_escape_string($link, $city);
/* this query with escaped $city will work */
if (mysqli_query($link, "INSERT into myCity (Name) VALUES ('$city')")) {
printf("%d Row inserted.\n", mysqli_affected_rows($link));
}
mysqli_close($link);
?>
Die obigen Bespiele erzeugen folgende Ausgabe:
Error: 42000 1 Row inserted.
Anmerkungen
Hinweis:
For those accustomed to using mysql_real_escape_string(), note that the arguments of mysqli_real_escape_string() differ from what mysql_real_escape_string() expects. The link identifier comes first in mysqli_real_escape_string(), whereas the string to be escaped comes first in mysql_real_escape_string().
Siehe auch
- mysqli_character_set_name() - Returns the default character set for the database connection
add a note
User Contributed Notes
mysqli::real_escape_string
dave at mausner.us
25-Feb-2011 08:48
Josef Toman
26-Feb-2010 07:14
For percent sign and underscore I use this:
<?php
$more_escaped = addcslashes($escaped, '%_');
?>
vita dot plachy at seznam dot cz
09-Nov-2007 12:37
The above can be managed by the following function:
<?php
function search_escape($str, $char = '\\')
{
return ereg_replace('[%_]', $char . '\0', $str);
}
?>
tobias_demuth at web dot de
10-Nov-2005 09:54
Note, that if no connection is open, mysqli_real_escape_string() will return an empty string!
arnoud at procurios dot nl
07-Oct-2004 11:05
Note that this function will NOT escape _ (underscore) and % (percent) signs, which have special meanings in LIKE clauses.
As far as I know there is no function to do this, so you have to escape them yourself by adding a backslash in front of them.